To fix the error “TypeError: ‘list’ object cannot be interpreted as an integer” in Python, there are some solutions we have effectively tested. Follow the article to better understand.
What causes error “TypeError: ‘list’ object cannot be interpreted as an integer”?
In Python, ‘list’ is a data type that allows storing various data types inside it and retrieving their values through the position of the elements. In Python, you can say ‘list’ is the most flexible data type.
The integer is a Python data type that represents negative integers, positive integers, and zero.
The TypeError in Python is thrown when you perform an unsupported operation on an object with an invalid data type.
The error “TypeError: ‘list’ object cannot be interpreted as an integer” happens when you try to pass a list to a function, but the function cannot interpret the list as an integer.
Example:
clubs = ["Arsenal", "Man City", "Newcastle", "Man United", "Liverpool", "Tottenham"] on_top4 = [True, True, True, True, False, False] for i in range(clubs): if on_top4[i] == True: print(f"{clubs[i]} participated in the Champion League") else: print(f"{clubs[i]} have missed the chance to participate in the Champion League")
Output:
for i in range(clubs):
TypeError: 'list' object cannot be interpreted as an integer
In the above example, the range()
function wants to be passed as an integer, but I pass it as a list, so the program gives an error.
How to solve this error?
Use len() function to iterate over list
We use the len()
function in Python to find the length of a string in Python. To count the number of elements in a Python list or count the number of elements in a Python array, we use the following syntax.
Syntax:
len(value)
Parameters:
- value: the object needs to calculate the length or count the number of elements.
Example:
- Make a ‘number’ list.
- Use
len()
function to return several elements in the ‘number’ list.
clubs = ["Arsenal", "Man City", "Newcastle", "Man United", "Liverpool", "Tottenham"] on_top4 = [True, True, True, True, False, False] # Use len() function returns several elements in the list 'clubs' for i in range(len(clubs)): if on_top4[i] == True: print(f"{clubs[i]} participated in the Champion League") else: print(f"{clubs[i]} has missed the chance to participate in the Champion League")
Output:
Arsenal participated in the Champion League
Man City participated in the Champion League
Newcastle participated in the Champion League
Man United participated in the Champion League
Liverpool has missed the chance to participate in the Champion League
Tottenham has missed the chance to participate in the Champion League
Remove the range() function
Example:
- Make a list.
- Remove the
range()
function. - Iterate the list directly.
clubs = ["Arsenal", "Man City", "Newcastle", "Man United", "Liverpool", "Tottenham"] on_top4 = [True, True, True, True, False, False] i = 0 for c in clubs: if on_top4[i] == True: print(f"{clubs[i]} participated in the Champion League") else: print(f"{clubs[i]} has missed the chance to participate in the Champion League") i = i + 1
Output:
Arsenal participated in the Champion League
Man City participated in the Champion League
Newcastle participated in the Champion League
Man United participated in the Champion League
Liverpool has missed the chance to participate in the Champion League
Tottenham has missed the chance to participate in the Champion League
Use the enumerate() function
In Python, the enumerate()
function adds a counter before each iterable and returns the result as an enumerated object.
Syntax:
enumerate(iterable, start=0)
Parameters:
- iterable: string, list, tuple, iterator.
- start:
enumerate()
starts the counter from start.
Example:
- Make a list.
- The
enumerate()
function returns the result as an enumeration object.
clubs = ["Arsenal", "Man City", "Newcastle", "Man United", "Liverpool", "Tottenham"] on_top4 = [True, True, True, True, False, False] for club in enumerate(clubs): if on_top4[club[0]] == True: print(f"{club[1]} participated in the Champion League") else: print(f"{club[1]} has missed the chance to participate in the Champion League")
Output:
Arsenal participated in the Champion League
Man City participated in the Champion League
Newcastle participated in the Champion League
Man United participated in the Champion League
Liverpool has missed the chance to participate in the Champion League
Tottenham has missed the chance to participate in the Champion League
Summary
If you have any questions about the error “TypeError: ‘list’ object cannot be interpreted as an integer” in Python, please leave a comment below. I will support your questions. Thanks for reading!
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My name is Jason Wilson, you can call me Jason. My major is information technology, and I am proficient in C++, Python, and Java. I hope my writings are useful to you while you study programming languages.
Name of the university: HHAU
Major: IT
Programming Languages: C++, Python, Java