If you are encountering the error “expression preceding parentheses of apparent call must have (pointer-to-) function type” in C++ and has difficulties fixing it. Now, let’s follow this guide with the explanation and examples below.
How does the error “expression preceding parentheses of apparent call must have (pointer-to-) function type” happen in C++?
Many causes make this error happen. But these are some common causes that many programmers encounter:
- Missing the colon after the access modifier.
- Missing required header inclusion and using.
- Trying to call a function that is not defined as a function.
Look at the example below.
#include <iostream>
template <typename T>
class Fraction {
int numerator ;
int denominator;
Fraction() {};
public // Missing the colon after the access modifier.
Fraction(int a, int b) :numerator(a), denominator(b) {};
void exportFraction const() {
cout << numerator<<"/"<<denominator; // Missing required header inclusion and using.
};
};
int main() {
Fraction<int> f(3,4);
f.exportFraction(); // Trying to call a function that is not defined as a function.
}Output
Expression preceding parentheses of apparent call must have (pointer-to-) function typeHow to solve this error?
Adding the colon after the access modifier
Review your code carefully and be sure that there is a colon after the access modifier (private, public, protected).
private:
protected:
public:
Adding required header inclusion and using
You can add the specified function by using command:
Syntax
using std:: theNameOfTheFucntion;
Look at the example below.
using std::cout;
using std::endl;Or you can declare using the std namespace. It has almost all the functions that you need for coding.
Syntax
using namespace std;
Rewriting the function properly
Check if your function is correct or not. The parentheses are after the name of the function.
Syntax:
type name(parameters)
Parameters:
- type: The return type.
- name: The name of the function.
- parameters: Optional. The parameters of the function.
Example:
void exportFraction() Look at the standard code after using these solutions.
#include <iostream>
using namespace std;
template <typename T>
class Fraction {
int numerator ;
int denominator;
Fraction() {};
public:
Fraction(int a, int b) :numerator(a), denominator(b) {};
void exportFraction() const {
cout << numerator<<"/"<<denominator;
};
};
int main() {
Fraction<int> f(3,4);
f.exportFraction();
}Output:
3/4 Summary
In this article, we have given you some ways to fix the error “Epression preceding parentheses of apparent call must have (pointer-to-) function type”. We hope it is helpful to you. If you have any questions or problems, please comment below. Thanks for reading!
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My name is Thomas Valen. As a software developer, I am well-versed in programming languages. Don’t worry if you’re having trouble with the C, C++, Java, Python, JavaScript, or R programming languages. I’m here to assist you!
Name of the university: PTIT
Major: IT
Programming Languages: C, C++, Java, Python, JavaScript, R
